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A simple LR circuit is connected to a ba...

A simple `LR` circuit is connected to a battery at time `t = 0`. The energy stored in the inductor reaches half its maximum value at time

A

`(R)/(L)In[sqrt(2)/(sqrt(2)-1)]`

B

`(R)/(L)In[(sqrt(2)-1)/sqrt(2)]`

C

`(R)/(L)In((sqrt(2)/(sqrt(2)-1))`

D

`(R)/(L)In[(sqrt(2)-1)/sqrt(2)]`

Text Solution

Verified by Experts

The correct Answer is:
C
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