In a series `LCR` circuit, at the frequencies `f_(1)` and `f_(2)` of `AC` source, the current amplitude falls to `(1)/(sqrt(2))` of the current amplitude at resonance. Then the value of `f_(2) - f_(1)` is

In a series LCR circuit, the frequencies at which the current amplitude is (1)/(sqrt(2)) mes the current amplitude at resonance are f_(1) and f_(2) (gt f_(1)). Find the frequency bandwidth of resonance which is defined as Deltaf=f_(2)-f_(1). Express your answer in terms of R and L. Assume that resonance frequency f_(0)gtgtDeltaf

At resonant frequency the current amplitude in series LCR circuit is

In the given figure , a series L-C-R circuit is connected to a variable frequency source of 230 V . The impedance and amplitude of the current at the resonating frequency will be

For the sereis LCR circuit shown in figure, the resonating frequency and current amplitude at resonance respectivley are

For the sereis LCR circuit shown in figure, the resonating frequency and current amplitude at resonance respectivley are

In a series LCR circuit, the frequency of the source is more than resonance frequency. The current in the circuit leads the voltage in phases(True/false).

For the series LCR circuit shown in the figure, what is the resonance frequency and the amplitude of the current at the resonating frequency