The rails ofa railway track are I.Sm apart and assumed to be insulated from one another. Calculate the EMF that will exist between the rails if a train is passing at 100 km/hr. Assume the horizontal component of earth's magnetic field is `0.36xx10^(-4)T` and `tan theta=1.036` where `theta` is the angle of dip.

A railway track running north south has two parrallel rails 1.0 m apart. Calculate the e.m.f. induced between the rails when a train passes at a speed of 90 km h^(-1) . Horizontal component of earth's magnetic field at that plane is 0.3 xx 10^(-4) T and angle of dip is 60^(@) .

A train is moving towards north with a speed of 25 m/s. if the vertical component of the earth's magnetic field is 0.2 xx 10^(-4) T, the emf induced in the axle 1.5 m long is

The two rails of a railway track separated by 1 metre and insulated from each other, are connected to a millivolmeter. What is the reading of the millivoltmeter when a train passes at a speed of 180 km//hour along the track? [The vertical component of earth's magnetic field is 2.0 xx 10^(-4) Wb//m^(2)] .

The two rails of a railway track, insulataed form each other and from the ground, are connected to a millivoltmeter. What will be the reading of the millivoltmeter when a train travels on the track at a speed of 180km h^(-1)? The vertical component of earth's magnetic field is 0.2 X 10^(-4) and the rails are separted by 1m.

An aeroplane is flying horizontally with a velocity of 360Km/hr. The distance between the tips of wings is 50m. If the vertical component of earth's magnetic field is 4xx10^(-4)T , induced EMF across the wings is:

In northern hemisphere, an airplane flies with a speed of 1000 km hr^(-1) towards east at constant height. Calculate the emf induced between the tips of the wings 50 m apart. The vertical component of Earth's magnetic field is 2 xx 10^(-5) T .

A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is 0.2xx10^(-4)T , then the emf developed between the two ends of hte conductor is

The angle of dip at a place is 37^(@) and the vertical component of the earth's magnetic field is 1.6xx 10^(-5)T. The earth's magnetic field at this place is (tan 37^@=3/4)