Home
Class 12
MATHS
The locus of the mid points of the chord...

The locus of the mid points of the chords of the circle `x^2+y^2+4x-6y-12=0` which subtends an angle of `pi/3` radians at its centre is

Text Solution

Verified by Experts

Equation of the circle,
`x^2+y^2+4x-6y -12 = 0`
Here, `g = 2, f = -3, c = -12`
`:.` Center of the circle will be `(-2,3)`.
Radius of the circle ` = sqrt(g^2+f^2-c) = sqrt(4+9+12) = 5`
Let `AB` is the chord and `C(h,k)` is the midpoint of `AB`.
We have to find locus of point `C`.
Let `O(-2,3)` is the center of the circle.
...
Promotional Banner

Similar Questions

Explore conceptually related problems

The locus of the mid points of the chords of the circle x^2+y^2+4x-6y-12=0 which subtends of angle of pi/3 radians at its centre is

The locus of the mid points of the chords of the circle x^2+y^2+4x-6y-12=0 which subtend an angle of pi/3 radians at its circumference is:

The locus of the mid points of the chords of the circle x^2+y^2+4x-6y-12=0 which subtend an angle of pi/3 radians at its circumference is: (A) (x-2)^2+(y+3)^2=6.25 (B) (x+2)^2+(y-3)^2=6.25 (C) (x+2)^2+(y-3)^2=18.75 (D) (x+2)^2+(y+3)^2=18.75

The locus of the mid points of the chords of the circle x^(2)+y^(2)+4x-6y-12=0 which subtend an angle of (pi)/(3) radians at its circumference is: (A) (x-2)^(2)+(y+3)^(2)=6.25(B)(x+2)^(2)+(y-3)^(2)=6.75(D)(C)(x+2)^(2)+(y-3)^(2)=18.75(D)(x+2)^(2)+(y+3)^(2)=18.75

The locus of the mid-points of the chords of the circle x^2+ y^2-2x-4y - 11=0 which subtends an angle of 60^@ at center is

The locus of the mid-points of the chords of the circles x^(2)+y^(2)-2x-4y-11=0 which subtends an angle of 60 at centre is