Minimum value of `f(x)=(6x^3-45 x^2+108 x+2)/(2x^3-15 x^2+36 x+1)` will occur then x is equal to

Minimum value of f(x)=4x^(3)-12x^(2)-36x is

Minimum value of f(x)=6x^(3) -9x^(2)-36x+24 is

The minimum value of f(x)=2x^2+3x+1 is

The minimum value of x^3-6x^2+9x+1 is

Minimum value of f(x)=(x-1)^(2)+(x-2)^(2)+..+(x-10)^(2) occurs at x=

Minimum value of f(x)=(x-1)^(2)+(x-2)^(2)+...+(x-10)^(2) occurs at

The maximum value of the function f(x)=(x^(4)-x^(2))/(x^(6)+2x^(3)-1) where x>1 is equal to:

Find the absolute maximum and minimum values of a function f given by f(x)=2x^3-15 x^2+36 x+1 on the interval [1,\ 5] .

Find the values of x, such that f(x)= 2 x^3 -15 x^2 +36x +1 is an increasing function