If I is the incenter of the circle inscribed in the triangle ABC and AI cuts BC at P, then

Let ABC be an isosceles triangle with base BC. If 'r' is the radius of the circle inscribed in triangle ABC and r_(1) is the radius of the circle escribed opposite to the angle A, then the product r_(1)r can be equal to

If f is the centre of a circle inscribed in a triangle ABC, then |vec BC|vec IA+|vec CA|vec IB+|vec AB|vec IC is

Let ABC be an isosceles triangle with base BC whose length is 'a'.If ' ' is the radius of the circle inscribed in the Delta ABC and r_(1) be theradius of the circle escribed opposite to the angle A,then the product rr_(1) can be equal to

A point I is the centre of a circle inscribed in a triangle ABC then show that abs(bar(BC))bar(IA)+abs(bar(CA))bar(IB)+abs(bar(AB))bar(IC)=bar(0)

If I is the centre of a circle inscribed in a triangle ABC , then |vec(BC)|vec(IA)+|vec(CA)|vec(IB)+|vec(AB)|vec(IC) is

A circle with centre P is inscribed in the triangle ABC. Side AB, side BC and side AC touch the circle at points L,M and N respectively. Radius of the circle is r. Prove that: A( triangle ABC)=(1)/(2)(AB+BC+AC)xxr .

In a right triangle ABC, right arigled at B ; BC = 12 cm and AB = 5 cm. Then the radius of the circle inscribed in the triangle is……cm.

If I is the incenter of a triangle ABC,then the ratio IA IB IC is equal to