(x^(2))/(36)+(y^(2))/(25)>=2

The eccentricity of the ellipse (x^(2))/(36)+(y^(2))/(25)=1 is

(x^(2))/(36)+(y^(2))/(16)=1

Tangents are drawn from a point on the circle x^(2)+y^(2)=11 to the hyperbola x^(2)/(36)-(y^(2))/(25)=1 ,then tangents are at angle:

For the given ellipse ,find the equation of directrix (i) (x^(2))/(25) + (y^(2))/(9) = 1 iii (x^(2))/(36) + (y^(2))/(16) = 1 (x^(2))/(49) + (y^(2))/(36) = 1 (iv) (x^(2))/(100) + (y^(2))/(400) = 1.

Find the eccentricity of the ellipse (i) (x^(2))/(16)+(y^(2))/(9)=1 (ii) (x^(2))/(64)+(y^(2))/(36)=1 (iii)25x^(2)+4y^(2)=100

Find the length of latus rectum of the ellipse (x^(2))/(25) + (y^(2))/(36) = 1 .

Find the equation of tangnets to the hyperbola (x^(2))/(25)-(y^(2))/(36)=1 , parallel to the line 3x-3y=0

The locus of midpoint of the chords of hyperbola (x^(2))/(25)-(y^(2))/(36)=1 which passes through the point (2,4) is a conic whose eccentricity is

Area bounded by the curves satisfying the conditions (x^(2))/(25)+(y^(2))/(36)le 1le(x)/(5)+(y)/(6) is given by

The number of terms in the expansion of (x^(2) + y^(2))^(25) – (x^(2) - y^(2))^(25) after simplification is