Let `f(x)` be a real valued function not identically zero satisfies the equation,`f(x + y^n) = f(x) + (f(y))^n` for all real `x & y and f' (0) leq 0` where `n (>1)` is an odd natural number. Find `f(10)`.

If f is a real valued function not identically zero,satisfying f(x+y)+f(x-y)=2f(x)*f(y) then f(x)

Let f(x) be a real valued function not identically zero such that f(x+y^(2n+1))=f(x)+(f(y))^(2n+1), n epsilon N and x, y epsilo R . If f'(0)ge0 , then f'(6) is

If a real valued function f(x) satisfies the equation f(x +y)=f(x)+f (y) for all x,y in R then f(x) is

If a real valued function f(x) satisfies the equation f(x+y)=f(x)+f(y) for all x,y in R then f(x) is

Let f(x) be a real valued function not identically zero, which satisfied the following conditions I. f(x + y^(2n + 1)) = f(x) + (f(y))^(2n+1), n in N, x, y are any real numbers. II. f'(0) ge 0 The value of f'(10), is

Let f(x) be a real valued function not identically zero, which satisfied the following conditions I. f(x + y^(2n + 1)) = f(x) + (f(y))^(2n+1), n in N, x, y are any real numbers. II. f'(0) ge 0 The value of f'(10), is

Let f(x) be a real valued function not identically zero, which satisfied the following conditions I. f(x + y^(2n + 1)) = f(x) + (f(y))^(2n+1), n in N, x, y are any real numbers. II. f'(0) ge 0 The value of f'(10), is