" 10."quad " As anfur "$6" sin "(180^(@)+theta)=cos(90^(@)+theta)

sin theta cos(90^(@)-theta)+cos theta sin(90^(@)-theta)

Prove that cos theta + "sin " (270^(@) +theta) - "sin "(270^(@) -theta) + "cos " (180^(@) +theta) =0

Evaluate : sin theta cos theta - (sin theta cos (90^(@) - theta) cos theta)/( sec (90^(@) - theta)) - (cos theta sin (90^(@) - theta) sin theta)/( cosec (90^(@) - theta))

Find 'x' from the equation: "cosec"(90^(@)-theta)-x "sin"(90^(@)-theta)"tan"(180^(@)+theta)="sin"(90^(@)+theta) .

Prove that sin (270^(@)-theta) sin (90^(@)-theta)-cos(270^(@)-theta) cos (90^(@)+theta)+1=0

Simplify: (i) (cos theta)/(sin (90^@ + theta)) + (sin (-theta))/(sin(180^(@) + theta)) - (tan(90^(@)+theta))/(cot theta)

If tan theta = -(5)/(12) and theta is not in the fourth quadrant then ( tan (90^(@)+ theta ) - sin(180^(@) - theta ))/( sin (270^(@)- theta ) + " cosec " (360^(@) - theta ))=

Write the value of sintheta cos(90^(@)-theta)+costheta sin(90^(@)-theta).