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Let p : 7 is not greater than 4 and q : ...

Let p : 7 is not greater than 4 and q : Paris is in France
be two statements. Then, `~(p vv q)` is the statement

A

7 is greater than 4 or Paris is not in France.

B

7 is not greater than 4 and Paris is not in France.

C

7 is not greater than 4 and Paris is in France.

D

7 is greater than 4 and Paris is not in France.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given statements and then apply the negation to the logical expression. 1. **Identify the Statements**: - Let \( p \): "7 is not greater than 4". - Let \( q \): "Paris is in France". 2. **Translate the Statements**: - The statement \( p \) can be interpreted as: "7 is less than or equal to 4" (which is false). - The statement \( q \) is true because Paris is indeed in France. 3. **Formulate the Logical Expression**: - We need to find the negation of the disjunction (logical OR) of \( p \) and \( q \), which is represented as \( \sim (p \lor q) \). 4. **Apply De Morgan's Law**: - According to De Morgan's Laws, the negation of a disjunction can be expressed as the conjunction (logical AND) of the negations: \[ \sim (p \lor q) = \sim p \land \sim q \] 5. **Negate Each Statement**: - Negate \( p \): - \( \sim p \): "7 is greater than 4" (which is true). - Negate \( q \): - \( \sim q \): "Paris is not in France" (which is false). 6. **Combine the Negated Statements**: - Now, we combine the negated statements using logical AND: \[ \sim (p \lor q) = \sim p \land \sim q \] - This translates to: "7 is greater than 4 AND Paris is not in France". 7. **Final Statement**: - Therefore, the final statement is: "7 is greater than 4 AND Paris is not in France". ### Summary of the Solution: The statement \( \sim (p \lor q) \) translates to: "7 is greater than 4 AND Paris is not in France".
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