Home
Class 12
MATHS
The normal from of the vector equation b...

The normal from of the vector equation `barr.(3hati-2hatj+2hatk)=14` is

A

`barr.((3)/(sqrt(17))hati-(2)/(sqrt(17))hatj+(2)/(sqrt(17))hatk)=12`

B

`barr.(3hati-2hatj+2hatk)=(12)/(sqrt(17))`

C

`barr.((3)/(sqrt(17))hati-(2)/(sqrt(17))hatj+(2)/(sqrt(17))hatk)=(12)/(sqrt(17))`

D

`barr.(3hati-2hatj+2hatk)=12`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • PLANE

    TARGET PUBLICATION|Exercise CRITICAL THINKING|58 Videos

  • PLANE

    TARGET PUBLICATION|Exercise COMPETATIVE THINKING|89 Videos

  • PAIR OF STRAIGHT LINES

    TARGET PUBLICATION|Exercise EVALUATION TEST|11 Videos

  • PROBABILITY DISTRIBUTION

    TARGET PUBLICATION|Exercise Evaluation test|5 Videos

Similar Questions

Explore conceptually related problems

Find the angle between the planes whose vector equations are barr *(2hati + 2hatj - 3hatk) = 5 and barr *(hati -2hatj+hatk) =7 .

The unit vector parallel to the resultant of the vectors 2hati+3hatj-hatk and 4hati-3hatj+2hatk is

If the line barr = (hati - 2hatj + hatk) + lambda(2hati + hatj + 2hatk) is parallel to the plane barr *(3hati - 2hatj + mhatk) = 14 , then the value of m is

The vector equation barr=hati-2hatj-hatk+t(6hatj-hatk) , represents a line passing through points

Find the cartesian form of the equation of the plane. barr = (hati + hatj) + s(hati - hatj + 2hatk) + t(hati + 2hatj +hatk) .