If x=a(1-costheta) , y=a(theta+sintheta)...

If `x=a(1-costheta)` , `y=a(theta+sintheta)` , then value of `(d^2y)/(dx^2)` at `theta=pi/2` is .

A

`1/a`

B

`-1/a`

C

a

D

`-a`

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The correct Answer is:

B

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