Home
Class 12
PHYSICS
When a metal slab is placed between the ...

When a metal slab is placed between the charged identical , parallel plates , the potential difference between the plates

A

decreases

B

increases

C

remains unchanged.

D

may increase or decrease

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATICS

    TARGET PUBLICATION|Exercise CRITICAL THINKING|67 Videos

  • ELECTROSTATICS

    TARGET PUBLICATION|Exercise COMPETITIVE THINKING|124 Videos

  • ELECTROMAGNETIC INDUCTION

    TARGET PUBLICATION|Exercise EVALUATION TEST|8 Videos

  • GRAVITATION

    TARGET PUBLICATION|Exercise EVALUATION TEST|24 Videos

Similar Questions

Explore conceptually related problems

A uniformly distributed space charge fills up the space between two large parallel plates separated by a distance d . The potential difference between the plates is equal to zero ? What will then be the field strength near the other plate ?

Displacement current is produced between the plates of a capacitor when potential difference between the plates

Separation between the plates of parallel plate capacitor is 5 mm. this capacitor, having air as the dielectric medium between the plates, is charged to a potential difference 25 V using a battery. The battery is then disconnected and a dielectric slab of thickness 3mm and dielectric constant K=10 is placed between the plates as shown. potential difference between the plates after the dielectric slab has been introduced is-

shows two metallic plates A and B placed . parallel to each other at a separaton d. A uniform . electric field E exists between the plates in the direction . from plate B to plate A. Find the potential difference . between the plates.

The capacitance of a parallel plate capacitor is 16 mu F . When a glass slab is placed between the plates, the potential difference reduces to 1/8th of the original value. What is dielectric constant of glass ?

A parallel plate capacitor with air between the plates is charged to a potential difference of 500 V and then insulated. A plastic plate is inserted between the plates filling the whole gap. The potential difference between the plates now becomes 75V. The dielectric constant of plastic is

Charges 2q and -3q are given to two identical metal plates of area of cross section A . the distance between the plates is d . Find the capacitance and potential difference between the plates.

The plates of parallel plate capacitor are charged upto 100V . A 2mm thick dielectric slab is inserted between the plates.Then to maintain the same potential difference,the distance between the plates is increased by 1.6mm . The dielectric constant of the slab is.

A parallel plate capacitor is connected to a cell. A metal plate of neglible thickness is inserted parallel to plates. (A) the capacitance remains same (B) the cell will supply more charge (c) Equal and opposite charges will appear pm two faces of metal plate (D) the potential difference between the plates will increase