Home
Class 12
PHYSICS
Two parallel metal plates 2.0 cm apart, ...

Two parallel metal plates 2.0 cm apart, are connected to a 200 V battery. A proton with a positive charge `1.6 xx 10^(-19)` C is located between the plates . The electric field intensity between the plates is

A

5000 V/m

B

10000 V/m

C

`3.2xx10^(-6) V//m`

D

`50,000 V//m`

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROSTATICS

    TARGET PUBLICATION|Exercise COMPETITIVE THINKING|124 Videos
  • ELECTROSTATICS

    TARGET PUBLICATION|Exercise EVALUATION TEST|14 Videos
  • ELECTROSTATICS

    TARGET PUBLICATION|Exercise EVALUATION TEST|14 Videos
  • ELECTROMAGNETIC INDUCTION

    TARGET PUBLICATION|Exercise EVALUATION TEST|8 Videos
  • GRAVITATION

    TARGET PUBLICATION|Exercise EVALUATION TEST|24 Videos

Similar Questions

Explore conceptually related problems

Find the electric field between two metal plates 3 mm- apart connected to 12 V battery.

A parallel plate capacitor of plate area A and plates separation distance d is charged by applying a potential V_(0) between the plates. The dielectric constant of the medium between the plates is K. What is the uniform electric field E between the plates of the capacitor ?

Knowledge Check

  • Two plates are 2cm apart, a potential difference of 10 volt is applied between them, the electric field between the plates is

    A
    `20 N//C`
    B
    `500 N//C`
    C
    `5 N//C`
    D
    `250 N//C`
  • A parallel plate air condenser is charged and then disconnected from the charging battery. Now the space between the plates is filled with a dielectric then, it electric field strength between the plates

    A
    increases while its capacity increases
    B
    increases while its capacity decreases
    C
    decreases while its capacity increases
    D
    decreases while its capacity decreases
  • A parallel -plate capacitor is connected to a cell. A sheet of dielectric and a metal sheet are now introduced between the plates of the capacitor, parallel to these plates. The electric intensity between the positive plate of the capcitor and the metal sheet is E_(2) , and between the metal sheet and the negatilve plate is E_(3) . Then

    A
    `E_(1)=E_(2)=E_(3)`
    B
    `E_(1)=E_(2)!=E_(3)`
    C
    `E_(1)!=E_(2)=E_(3)`
    D
    `E_(1)!=E_(2)!=E_(3)`
  • Similar Questions

    Explore conceptually related problems

    A parallel plate air capacitor is made using two square plates each of side 0.2 m, spaced 1 cm apart. It is connected to a 50V battery. (a) What is the capacitance ? (b) What is the charge on each plate ? (c) What is the energy stored in the capacitor ? (d) What is the electric field between the plates ? (e) If the battery is disconnected and then the plates are pulled apart to a separation of 2 cm, what are the answers to the above parts ?

    Four identical metal plates are arranged as shown plates 1 and 4 are connected by a connecting wire. A battery of emf V volts is connected between plates 2 and 3. The electric field between plates 3 and 4 is (2V)/(Kd) . Find the value of K

    A parallel plate air capacitor is made using two plates 0.2 m square , spaced 1 cm apart . It is connected to a 50V battery. (a) what is the capacitance ? (b) what is the charge one each plane ? (c) what is energy stored in the capacitor ? (d) what is the electric field between the plates ? (e) If the battery is disconnected and then the plates are pulled apart to a separation of 2 cm , what are the answer to the above parts ?

    Two plates are at potentials -10 V and +30 V . If the separation between the plates be 2 cm . The electric filed between them is

    An uncharged parallel plate capacitor is connected to a battery. The electric field between the plates is 10V/m. Now a dielectric of dielectric constant 2 is inserted between the plates filling the entries space. The electric field between the plates now is