Force between two identical charges plac...

Force between two identical charges placed at a distance of `r` in vacuum is `F`.Now a slab of dielectric constant 4 is inserted between these two charges . If the thickness of the slab is `r//2`, then the force between the charges will becomes

`(F)/(3)`

`(F)/(2)`

`(F)/(4)`

`(4F)/(9)`

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