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Latent heat of vaporisation of water,

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`L_("vap")=540 cal // g `
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Is it possible that water evaporates from a spherical drop of water just by means of surface energy supplying the necessary latent heat of vaporisation? The drop does not use its internal thermal energy and does not receive any heat from outside. It is known that water drops of size less than 10^(–6) m do not exist. Latent heat of vaporisation of water is L = 2.3 × 10^(6) Jkg^(–1) and surface tension is T = 0.07 Nm^(–1) .

At 0^@C a thermally isolated container has 200 g of water. When air above water is pumped out, then some of water evaporates and some of it freezes. What will be the mass of ice formed on freezing when there will be no water left in container? Latent heat of vaporisation of water = 2.2 xx 10^6 J/kg and latent heat of fusion of ice = 3.37 xx 10^5 J/kg.

1 g of water, of volume 1 cm^3 at 100^@C , is converted into steam at same temperature under normal atmospheric pressure (= 1 xx 10^5 Pa) . The volume of steam formed equals 1671 cm^3 . If the specific latent heat of vaporisation of water is 2256 J/g, the change in internal energy is

A thermally insulated pot has 200 g ice at temperature 0^(@)C . How much steam of 100^(@)C has to be mixed to it, so that water of temperature 40^(@)C will be obtained? (Given: Latent heat of melting of ice = 80 cal/g, latent heat of vaporisation of water = 540 cal/g, specific heat of water = I " cal/g " ^(@)C)