Explain by writing a reaction, what will happen when pieces of sodium metal are put in n-propyl alcohol.

Explanation

When pieces of sodium metal are put in n-propyl alcohol, hydrogen gas is produced and the other product formed is sodium n-propoxide.
The reaction is
`underset("alcohol")underset("n-Propyl")(2CH_(3)CH_(2)CH_(2)OH)+underset("Sodium")(2Na)rarr underset("Sodium n-propoxide")(2CH_(3)CH_(2)CH_(2)O-Na^(+))+underset("Hydrogen")(H_(2)darr)`