[sqrt(1)],[=],[1],[0],[11],[0]

If A=[[1,1],[0,1]],B=[[0,1],[1,0]] then AB=

Select the correct option from the given alternatives. The inverse of [[0,1],[1,0]] i] [[1,1],[1,1]] ii] [[0,1],[1,0]] iii] [[1,0],[0,1]] iv] None of these

Show that [[1,2,3],[0,1,0],[1,1,0]] [[-1,1,0],[0,-1,1],[2,3,4]] ne [[-1,1,0],[0,-1,1],[2,3,4]][[1,2,3],[0,1,0],[1,1,0]]

Show that: [[1,2,3],[0,1,0],[1,1,0]][[-1,1,0],[0,-1,1],[2,3,4]] ne [[-1,1,0],[0,-1,1],[2,3,4]][[1,2,3],[0,1,0],[1,1,0]]

The solution of the equation [[1,0 ,1],[-1,1 ,0],[0 ,-1,1]][[x],[ y] ,[z]]=[[1],[ 1],[ 2]] is

If [[1,3],[0,1]]A=[[1,1],[0,-1]] then the value of A is

If A=[[0,1],[1,0]] , then A^2 is equal to: (a) [[0,1],[1,0]] (b) [[1,0],[0,1]] (c) [[1,0],[1,0]] (d) [[0,0],[1,1]]

If A=[[x,1],[1,0]] and A^2=I , then A^(-1) is equal to: a) [[0,1],[1,0]] b) [[1,0],[0,1]] c) [[1,1],[1,1]] d) [[0,0],[0,0]]

Show that [[1,1],[0,1]]^2 = [[1,3],[0,1]]

If [[1,3] , [0,1]] A = [[1,1] , [0,-1]] then find the value of A