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If log, 3 9log, 4 10 log, 8x then x (1) ...

If log, 3 9log, 4 10 log, 8x then x (1) 5 (2) 1110 (4) 25 (3) 10

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`4^(log_9 3)+9^(log_2 4) = 10^(log_x 8x)`
`=>4^(log_9 9^(1/2))+9^(log_2 2^2) = 10^(log_x 8 + log_x x)`
`=>4^(1/2log_9 9)+9^(2log_2 2) = 10^(log_x 8 + 1)`
`=>4^(1/2)+9^2 = 10*10^(log_x 8)`
`=>2+81 = 10*10^(log_x 8)`
`=>83/10 = 10^(log_x 8)`
`=>log_10 (83/10) = log_10 (10^(log_x 8))`
`=>log_10(8.3) = log_x 8`
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