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The solution to the inequality |2x-1| lt...

The solution to the inequality |2x-1| lt 6 is

A

`x lt - 5/2` or `x gt 7/2`

B

`-5/2 lt x lt 7/2`

C

`x lt -7/2` or `x gt 5/2`

D

`-7/2 lt x lt 5/2`

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The correct Answer is:
To solve the inequality |2x - 1| < 6, we can break it down into two separate inequalities based on the property of absolute values. Here's the step-by-step solution: ### Step 1: Set up the inequalities The inequality |2x - 1| < 6 can be rewritten as two separate inequalities: 1. 2x - 1 < 6 2. -(2x - 1) < 6 ### Step 2: Solve the first inequality 1. Start with the first inequality: \[ 2x - 1 < 6 \] 2. Add 1 to both sides: \[ 2x < 6 + 1 \] \[ 2x < 7 \] 3. Divide both sides by 2: \[ x < \frac{7}{2} \] ### Step 3: Solve the second inequality 1. Now, solve the second inequality: \[ -(2x - 1) < 6 \] This simplifies to: \[ -2x + 1 < 6 \] 2. Subtract 1 from both sides: \[ -2x < 6 - 1 \] \[ -2x < 5 \] 3. Divide both sides by -2 (remember to reverse the inequality sign): \[ x > -\frac{5}{2} \] ### Step 4: Combine the results From the two inequalities, we have: 1. \( x < \frac{7}{2} \) 2. \( x > -\frac{5}{2} \) Combining these results gives us: \[ -\frac{5}{2} < x < \frac{7}{2} \] ### Final Answer The solution to the inequality |2x - 1| < 6 is: \[ \boxed{\left(-\frac{5}{2}, \frac{7}{2}\right)} \] ---
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