" (i) "[kx+2y=5],[3x+y=1]

For what vlaue of k given lines are intersecting. kx + 2y = 5, 3x + y =1

For what value of k pair of equation has independent solution kx + 2y = 5, 3x + y =1

Value of k for which system of equations kx + 2y = 5, 3x + y =1 has unique solution is

{:(kx + 2y = 5),(3x + y = 1):} Find the value of k for which given lines are not parallel to each other.

Rajesh want to chose a best plan for his mobile phone. He has 2 options available with him. The first plan of company A, cost Rs 20 per month, with costing an additional 25 paise per minute. The second plan of company B charge Rs 40 per month, but calls cost 8 paise per minute. These two situations are shown below in the form of linar equations. The total cost of the two company's are given as : y =0.25 x + 20 and y = 0.8x + 40 Where, x is the minutes used any y is the total cost per month. If the system of pair of linear equation kx - 2y = 5, 3x + y =1 has a unique solution then the value of k is :

Find the value of k for which the following system of equations has a unique solution: kx+2y=5,quad 3x+y=1

Find the value of 'k' for which the system of linear equation kx + 2y = 5 and 3x + y =1 has zero solutions

The pair of linear equations kx+2y=5 and 3x+y=1 has unique solution if a)k=0 b) k!=6 c)k=2 d)k=3

For what value of k, the system of equations kx+2y=0, and 3x+y=1 will be coincident?

3x-y=2,5x-2y=1