If `log_(cos x) sin x > 2 and `0

If log_(cos x)sin x>=2 and x in[0,3 pi] then sin x lies in the interval

Statement I Common value(s) of 'x' satisfying the equation . log_(sinx )( sec x +8) gt o and log_(sinx) cos x + log_(cos x ) sin x =2 in (0, 4pi) does not exist. Statement II On solving above trigonometric equations we have to take intersection of trigonometric chains given by sec x gt 1 and x = n pi +(pi)/(4), n in I

Statement I Common value(s) of 'x' satisfying the equation . log_(sinx )( sec x +8) gt o and log_(sinx) cos x + log_(cos x ) sin x =2 in (0, 4pi) does not exist. Statement II On solving above trigonometric equations we have to take intersection of trigonometric chains given by sec x gt 1 and x = n pi +(pi)/(4), n in I

If log_(cos x)sin x + log_(sin x)cos x=2 then x =

The smallest positive x satisfying log_sin x cos x+log_(cos x) (sin x)=2 , when x in (0,pi/2) , is

If: (log_(cos x) sin x) + (log_(sin x)cos x)=2 , then, in general, x=

2.The value of x satisfying the equation log_(cos x)sin x=1 , where 0< x < (pi)/2 is

Solve: log_(cosx) sin x + log_(sin x) cos x = 2 .

If y={log_(cos x)sin x}{log_(sin x)cos x)^(-1)+sin^(-1)((2x)/(1+x^(2))) find (dy)/(dx) at x=(pi)/(4)

The smallest positive x satisfying log_(cos x)sin x+log_(sin x)cos x=2 is :