In the fig., `seg.PR_|_seg.BC` ,`seg.AS_|_seg.BC`, `seg.QT_|_seg.BC`. Find the ratio :

In the adjoining figure, seg AD_|_side BC , seg BE_|_side AC , seg CF_|_side AB .Point O is the orthocentre.Prove that,Point O is the incentre of triangle DEF .

In the following figure, seg AB_|_"seg BC, seg DC" _|_"seg BC". If AB = 2 and DC = 3, find (A(DeltaABC))/(A(DeltaDCB)).

In the following figure seg PS_|_ seg RQ , seg QT_|_ seg PR . If RQ=6,PS=6 and PR=12 , then find the QT .

In the adjoining figure , seg ML || seg BC , seg NL || seg DC. Prove that AM : AB = AN: AD .

In the figure, seg PQ|| side BC and seg QR|| side AB . (i) Find (AQ)/(QC) . (ii) What would be (CR)/(RB) ? (iii) Is (BP)/(PA)=(BR)/(RC) ?

In the given figure, seg AE bot seg BC and seg DF bot seg BC. Find i. (A(DeltaABC))/(A(DeltaDBC)) ii. (A(DeltaDBF))/(A(DeltaDFC)) iii. (A(DeltaAEC))/(A(DeltaDBF))

In the given figure, seg AE bot seg BC and seg DF bot seg BC. Find i. (A(DeltaABC))/(A(DeltaDBC)) ii. (A(DeltaDBF))/(A(DeltaDFC)) iii. (A(DeltaAEC))/(A(DeltaDBF))

In the figure given seg PA, seg QB, seg RC and seg SD are perpendicular to line AD. AB=60, BC=70, CD=80and PS=280, then find PQ, QR and RS.

In the adjoining figure, seg PA , seg QB, seg RC and seg SD are perpendicular to line AD. AB = 60, BC = 70, CD = 80, PS = 280, then find PQ, QR and RS.

In the adjoining figure, seg PA , seg QB, seg RC and seg SD are perpendicular to line AD. AB = 60, BC = 70, CD = 80, PS = 280, then find PQ, QR and RS.