(1)/(ab)+(1)/(bc)+(1)/(ca)

(1)/(bc)+(1)/(ca)+(1)/(ab)=

If a,b,c are in A.P,prove that (1)/(bc),(1)/(ca),(1)/(ab), is also in A.P.

In a triangle A BC, (1)/(bc) + (1)/(ca) + (1)/(ab) = (k)/(2) , then k=

The vertices of a triangle are (ab,(1)/(ab)),(bc,(1)/(bc)),(ca,(1)/(ca)) where a,b,c are roots of the equation x^(3)-3x^(2)+6x+1=0 then centroid is

If a,b,c are non-zero real numbers, then |(1,ab,(1)/(a)+(1)/(b)),(1,bc,(1)/(b)+(1)/(c)),(1,ca,(1)/(c)+(1)/(a))| is a)0 b)bc+ca+ab c) a^(-1)+b^(-1)+c^(-1) d)None of these

If a,b,c are in A.P then a+(1)/(bc),b+(1)/(ca),c+(1)/(ab) are in