[" 2."(9x)/(7-6x)=15],[" 5."(7y+4)/(y+2)=(-4)/(3)]

Solve for x and y : (y+7)/(5)=(2y-x)/(4)+3x-5 (7-5x)/(2)+(3-4y)/(6)=5y-18

Solve : (7 + x)/(5) - (2x - y)/(4) = 3y - 5 (5y - 7)/(2) + (4x - 3)/(6) = 18 - 5x

(6x-7)/(2)+(9-2x)/(5)=12+(x)/(4)-(2)/(3)+(4x)/(3)

Find the value of x+y from the following equation: 2[(x,5),(7y,-3)]+[(3,-4),(1,2)]=[(7,6), (15,-4)]

Projection of line (x+1)/2+(y+1)/(-1)=(z+3)/4 on the plane x+2y+z=6; has equation x+2y+z-6=0=9x-2y-5z-8 b. x+2y+z+6=0,9x-2y+5z=4 c. (x-1)/4=(y-3)/(-7)=(z+1)/(10) d. (x+3)/4=(y-2)/7=(z-7)/(-10)

Find each of the following products: (i) (x + 6) (x + 6) (ii) (4x + 5y) (4x + 5y) (iii) (7a + 9b) (7a + 9b) (iv) ((2)/(3) x + (4)/(5)y) ((2)/(3) x + (4)/(5) y) (v) (x^(2) + 7)(x^(2) + 7) (vi) ((5)/(6) a^(2) + 2) ((5)/(6) a^(2) + 2)

(x)/(2) - ( y )/(9) = 6, ( x) /( 7) + ( y ) /(3) = 5 .

Solve by cross-multiplication method. (i) 8x-3y=12,5x=2y +7 (ii) 6x+ 7y -11 =0, 5x+ 2y =13 (iii) (2)/(x)+(3)/(y) =5, (3)/(x) -(1)/(y) +9=0

Find the value of 'x' and 'y' if : 2[(x,7),(9,y-5)]+[(6,-7),(4,5)]=[(10,7),(22,15)]

If 7x - 15y = 4x + y , find the value of x: y . Hence, use componendo and dividendo to find the values of : (i) (9x + 5y)/(9x - 5y) (iI) (3x^(2) + 2y^(2))/(3x^(2) - 2y^(2))