[" 4."3x+2y+25=0],[2x+y+10=0]

Solve the following system of equations by method of cross-multiplication: 3x+2y+25=0,quad 2x+y+10=0

Solve the following system of equations by method of substitution: 3x+2y+25=0,\ \ \ \ 2x+y+10=0

The area of the triangle formed by the lines 2x+y-4=0, 3x+2y-5=0, x+y+1=0 is

The perimeter of a parallelogram whose sides are represented by the lines x+2y+3=0 , 3x+4y-5=0,2x+5=0 and 3x+4y-10=0 is equal to

Solve the system: x + y - 2z = 0, 2x - 3y + z = 0, 3x - 7y + 10z = 0, 6x - 9y + 10z = 0.

x- y + 3 = 0, 2x + 3y - 4 = 0 .

{:(3x - 2y = 4),(5x - 2y = 0):}

3x + 4y - 10 = 0 2x - 2y-2=0

Show that the straight lines : x-y-1=0, 4x + 3y = 25 and 2x-3y + 1 = 0 are concurrent.