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" (ii) "3x+4y=10" 24궈 "2x-2y=2.2...

" (ii) "3x+4y=10" 24궈 "2x-2y=2.2

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3x + 4y = 10, 2x-2y = 2

Solve 3x+4y=10; 2x-2y=2

3x + 4y - 10 = 0 2x - 2y-2=0

Find the values of (x-y) , if (i) 3x + 4y = 11 , 4x + 3y = 10 (ii) 3x + 2y = 8 , 2x + 3y = 7

The equation of the tangent to the circle x^2+y^2=25 passing through (-2,11) is (a) 4x+3y=25 (b) 3x+4y=38 (c) 24 x-7y+125=0 (d) 7x+24 y=250

The equation of the tangent to the circle x^2+y^2=25 passing through (-2,11) is (a) 4x+3y=25 (b) 3x+4y=38 (c) 24 x-7y+125=0 (d) 7x+24 y=250

The equation of the tangent to the circle x^2+y^2=25 passing through (-2,11) is (a) 4x+3y=25 (b) 3x+4y=38 (c) 24 x-7y+125=0 (d) 7x+24 y=250

The equation of the circle of radius 5 in the first quadrant which touches the x-axis and the line 3x-4y=0 is x^2+y^2-24 x-y-25=0 x^2+y^2-30 x-10 y+225=0 x^2+y^2-16 x-18 y-64=0 x^2+y^2-20 x-12 y+144=0

The equation of the circle of radius 5 in the first quadrant which touches the x-axis and the line 3x-4y=0 is x^(2)+y^(2)-24x-y-25=0x^(2)+y^(2)-30x-10y+225=0x^(2)+y^(2)-16x-18y-64=0x^(2)+y^(2)-20x-12y+144=0

Equation of radical axis of the circles x^(2) + y^(2) - 3x - 4y + 5 = 0 and 2x^(2) + 2y^(2) - 10x - 12y + 12 = 0 is