[" The affere "],[" (i) "81^(1/2)]

The value of [{(81)^(-1/2)}^(-1/4)]^2

Faqtorise (i). x^(2)-81

Find the value of 1/(81^n)-(10)/(81^n)C_1+(10^2)/(81^n)C_2-(10^3)/(81^n)C_3++(10^(2n))/(81^n) .

Find the value of 1/(81^n)-(10)/(81^n)^(2n)C_1+(10^2)/(81^n)^(2n)C_2-(10^3)/(81^n)^(2n)C_3++(10^(2n))/(81^n) .

Find the value of (1)/(81^(n))-(10)/(81^(n))^(2n)C_(1)+(10^(2))/(81^(n))^(2n)C_(2)-(10^(3))/(81^(n))^(2n)C_(3)+...+(10^(2n))/(81^(n))

Find the value of 1/(81^n)-(10)/(81^n)^(2n)C_1+(10^2)/(81^n)^(2n)C_2-(10^3)/(81^n)^(2n)C_3++(10^(2n))/(81^n)

The value of (1)/(81^(n))-(10)/(81^(n)).""^(2n)C_(2)-(10^(3))/(81^(n)).""^(2n)C_(3)+…+((10)^(2n))/(81^(n)) is

If I(m)=int_(0)^(pi)log_(e)(1-2mcosx+m^(2))dx , Then find the value of I(81/9)

the value of (1)/((81)^n)-^(2n) C_1. ((10)^2)/((81)^n)+ ^(2n) C_1 ((10)^2)/((81)^n)…....+((10)^2n)/((81)^n) is

((81)^(-2))^(1/4)=