The product of 4 consecutive even numbers is always divisible by (B) 768 (A) 600 (D) 384 (C) 864

Explanation

Let `4` consecutive numbers are `2n,2n+2,2n+4,2n+6.`

Then, `2n*(2n+2)*(2n+4)*(2n+6) = 2^4(n(n+1)(n+2)(n+3))`

Now, for minimum value, we will put `n = 1`.

Then,

`2^4(n(n+1)(n+2)(n+3)) = 16**1**2**3**4 = 384`

Therefore, product of `4` consecutive even numbers is divisible by `384`.