" (b) "x=a cos theta,y=b sin theta

If x =a cos theta , y =b sin theta then (dy)/(dx) =

The locus of the point x=a cos theta, y=b sin theta is

The locus of the point x=a+b cos theta y=b+a sin theta is

x=a cos theta,y=b sin theta then find dy/dx

Area of a triangle whose vertices are (a cos theta, b sin theta) , ( - a sin theta , b cos theta) " and " ( - a cos theta, - b sin theta) is

Eliminate theta between the equation : x =a cos theta + b sin theta, y =a sin theta- b cos theta .

Show that : x=a cos theta - b sin theta and y = a sin theta + b cos theta , represent a circle where theta is the parameter.

Show that : x=a cos theta - b sin theta and y = a sin theta + b cos theta , represent a circle where theta is the parameter.

If x=a cos^(3)theta,y=b sin^(3)theta, then

If x = a cos^3 theta, y = b sin^3 theta , then