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A capacitor of capacitance 3muF is first...

A capacitor of capacitance `3muF` is first charged by connecting it across a 10 V battery by closing key `K_(1)`. Then it is allowed to get discharged through `2 Omega` and `4 Omega` resistors by closing the key `K_(2)`. The total energy dissipated in the `4 Omega` resistor is equal to

A

0.5 mJ

B

0.05 mJ

C

0.1 mJ

D

0.2 mJ

Text Solution

Verified by Experts

The correct Answer is:
C
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