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Two capacitors C(1) and C(2) are charged...

Two capacitors `C_(1)` and `C_(2)` are charged to same potential `V`, but with opposite polarity as shown in the figure. The switches `S_(1)` and `S_(2)` are then closed

A

Potential difference across two capacitors are same and is given by `((C_1 - C_(2)) V)/(C_(1) + C_(2))`

B

Potential difference across two capacitors are same and is given by `((C_(1) + C_(2))/(C_(1) - C_(2)))V`

C

Ratio of final energy to initial energy of the system is given by `((C_(1) - C_(2))^(2))/(C_(1) + C_(2))^(2)`

D

Ratio of final energy to initial energy of the system is given by `((C_(1))^(2))/((C_(1) + C_(2))^(2))`

Text Solution

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The correct Answer is:
A, C
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