Home
Class 11
PHYSICS
A capacitance balance is shown in figure...

A capacitance balance is shown in figure. The balance has a weight attached on one side and capacitor that has a variable gap width on other side. Assume the upper plate of the capacitor has negligibles mass. When the potential difference between the plates is `V_(0)`, the attractive force between the plates balance the weight of the hanging mass, Then:

A

Equilibrium of weight is stable

B

Equilibrium of weight is unstable

C

Value of `V_(0)` required to balance the weight is given by `V_(0) = d sqrt((2 Mg)/(espi_(0)A))`

D

for a small displacement block of mass M executes simple harmonic motion

Text Solution

Verified by Experts

The correct Answer is:
B, C
Promotional Banner

Similar Questions

Explore conceptually related problems

A capacitance balance is shown in the figure. The balance has a block pulley system attached on one side and a capacitor that has a variable gap width on the other side. Assume upper plate of the capacitor has negligible mass. When the separation between the plate is 1/(sqrt(5)) meter, the attractive force between the plates balances the pulley block system. Then find value of V_(0) in volts (EMF of battery). (Take area of the plate =20/(3epsilon_(0))m^(2) )

If Q is the charge on the pates of a capacitor of capacitances C,V the potential difference between the plates, s the area of each plate and d the distance between the plates, the force of attraction between the plates is-

A capacitor has a capacitance of 7.28 muF . What amount of charge must be placed on each of its plates to make the potential difference between its plates equAl to 25.0 V ?

One plate of a capacitor of capacitance 2muF has total charge +10muC and its other plate has total charge +40mUC . The potential difference between the plates is (in Volt).

The force between the plates of a parallel plate capacitor of capacitance C and distance of separation of the plates d with a potential difference V between the plates, is.

A parallel plate air capacitor has capcity C distance of separtion between plates is d and potential difference V is applied between the plates force of attraction between the plates of the parallel plate air capacitor is

A variable capacitor has n plates and the distance between two successive plates is d. determine its capacitance.

An air parallel plate capacitor has capacity C. When the area and distance between the plates is doubled, the capacitance is C_(1) , then (C_(1))/(C ) is -

The plates of capacitor are charged to a potential difference of 100V and then connected across a resistor.When the potential difference between the plates of the capacitor is 60V ,what is the fraction of the stored energy which has been dissipated?