Match the following . When an independent positive charge moves from higher potential to lower potential, then `{:(,"Table - 1",,"Table - 2",),((A),"its kinetic energy",(P),"will remain constant",),((B),"its potential energy",(Q),"will decrease",),((C),"its mechanical energy",(R),"will increase",):}`
Text Solution
AI Generated Solution
The correct Answer is:
To solve the question, we need to analyze the behavior of a positive charge moving from a region of higher electric potential to a region of lower electric potential. We will match the quantities in Table - 1 with their corresponding effects in Table - 2.
### Step-by-Step Solution:
1. **Understanding the Movement of Charge**:
- When a positive charge moves from a higher potential to a lower potential, it is moving in the direction of the electric field.
2. **Kinetic Energy (Option A)**:
- As the charge moves from higher potential to lower potential, it will gain kinetic energy due to the work done by the electric field on the charge.
- Therefore, the kinetic energy of the charge will **increase**.
- **Match**: (A) its kinetic energy → (R) will increase.
3. **Potential Energy (Option B)**:
- The potential energy of a charge in an electric field is given by the formula \( U = qV \), where \( q \) is the charge and \( V \) is the electric potential.
- As the charge moves to a lower potential, its potential energy will decrease.
- **Match**: (B) its potential energy → (Q) will decrease.
4. **Mechanical Energy (Option C)**:
- The mechanical energy of the system is the sum of kinetic energy and potential energy.
- Since the potential energy decreases and the kinetic energy increases, the total mechanical energy remains constant (assuming no non-conservative forces are acting).
- **Match**: (C) its mechanical energy → (P) will remain constant.
### Final Matching:
- (A) its kinetic energy → (R) will increase
- (B) its potential energy → (Q) will decrease
- (C) its mechanical energy → (P) will remain constant
### Summary of Matches:
- A → R
- B → Q
- C → P
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