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Match the following . When an independen...

Match the following . When an independent positive charge moves from higher potential to lower potential, then
`{:(,"Table - 1",,"Table - 2",),((A),"its kinetic energy",(P),"will remain constant",),((B),"its potential energy",(Q),"will decrease",),((C),"its mechanical energy",(R),"will increase",):}`

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The correct Answer is:
To solve the question, we need to analyze the behavior of a positive charge moving from a region of higher electric potential to a region of lower electric potential. We will match the quantities in Table - 1 with their corresponding effects in Table - 2. ### Step-by-Step Solution: 1. **Understanding the Movement of Charge**: - When a positive charge moves from a higher potential to a lower potential, it is moving in the direction of the electric field. 2. **Kinetic Energy (Option A)**: - As the charge moves from higher potential to lower potential, it will gain kinetic energy due to the work done by the electric field on the charge. - Therefore, the kinetic energy of the charge will **increase**. - **Match**: (A) its kinetic energy → (R) will increase. 3. **Potential Energy (Option B)**: - The potential energy of a charge in an electric field is given by the formula \( U = qV \), where \( q \) is the charge and \( V \) is the electric potential. - As the charge moves to a lower potential, its potential energy will decrease. - **Match**: (B) its potential energy → (Q) will decrease. 4. **Mechanical Energy (Option C)**: - The mechanical energy of the system is the sum of kinetic energy and potential energy. - Since the potential energy decreases and the kinetic energy increases, the total mechanical energy remains constant (assuming no non-conservative forces are acting). - **Match**: (C) its mechanical energy → (P) will remain constant. ### Final Matching: - (A) its kinetic energy → (R) will increase - (B) its potential energy → (Q) will decrease - (C) its mechanical energy → (P) will remain constant ### Summary of Matches: - A → R - B → Q - C → P
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