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Five identical cells are connected in pa...

Five identical cells are connected in parallel. Now, polarity of one of the cells is reversed. Percentage change in equivalent emf will be

A

-0.1

B

-0.2

C

-0.4

D

-0.6

Text Solution

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The correct Answer is:
To solve the problem of finding the percentage change in equivalent EMF when one of the five identical cells connected in parallel has its polarity reversed, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Configuration**: - We have 5 identical cells connected in parallel. Let the EMF of each cell be \( E \) and the internal resistance of each cell be \( R \). 2. **Calculate Initial Equivalent EMF**: - When all cells are connected in parallel, the equivalent EMF (\( E_{eq} \)) is simply the EMF of one cell, since they are identical and in parallel: \[ E_{eq\_initial} = E \] 3. **Effect of Reversing One Cell**: - When the polarity of one cell is reversed, its EMF becomes \(-E\). Thus, we now have: - Four cells with EMF \( E \) - One cell with EMF \(-E\) 4. **Calculate New Equivalent EMF**: - The equivalent EMF can be calculated using the formula: \[ E_{eq\_new} = \frac{E}{R} + \frac{E}{R} + \frac{E}{R} + \frac{E}{R} - \frac{E}{R} \] - This simplifies to: \[ E_{eq\_new} = \frac{4E - E}{R} = \frac{3E}{R} \] - The total resistance in the parallel circuit remains: \[ R_{eq} = \frac{R}{5} \quad \text{(since there are 5 identical resistances in parallel)} \] 5. **Final Equivalent EMF**: - Therefore, the new equivalent EMF is: \[ E_{eq\_new} = \frac{3E}{5} \] 6. **Calculate Percentage Change in EMF**: - The change in EMF (\( \Delta E \)) is given by: \[ \Delta E = E_{eq\_new} - E_{eq\_initial} = \frac{3E}{5} - E = \frac{3E - 5E}{5} = -\frac{2E}{5} \] - To find the percentage change: \[ \text{Percentage Change} = \left( \frac{\Delta E}{E_{eq\_initial}} \right) \times 100 = \left( \frac{-\frac{2E}{5}}{E} \right) \times 100 = -40\% \] ### Conclusion: The percentage change in equivalent EMF when one cell's polarity is reversed is \(-40\%\), indicating a decrease in EMF.
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