A galvanometer, together with an unknown resistance in series, is connected across two identical batteries of each `1.5 V`. When the batteries are connected in series,the galvanometer records a current of `1 A`, and when the batteries are connected in parallel, the current is `0.6 A`. In this case, the internal resistance of the battery is `1//'**' Omega`.
What is the value of '*'?

Options

A. `r = (2)/(3) Omega`
B. `r = (2)/(5) Omega`
C. `r = (1)/(3) Omega`
D. `r = (3)/(2) Omega`

Answer

C