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Steam at 100^(@)C is added slowly to 140...

Steam at `100^(@)C` is added slowly to 1400 gm of water at `16^(@)C` until the temperature of water is raised to `80^(@)C`. The mass of steam required to do this is (`L_(V)`= 540 cal/g)

A

160 g

B

120 g

C

250 g

D

320 g

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The correct Answer is:
A
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When m gram of steam at 100^(@) C is mixed with 200 gm of ice at 0^(@)C . it results in water at 40^(@) C . Find the value of m in gram . (given : Latent heat of fusion ( L_f ) = 80 cal/gm, Latent heat of vaporisation ( L_v ) = 540 cal/gm., specific heat of water ( C_w )= 1 cal/gm/C)

The amount of steam at 100^@ C that should be passed into 600 g of water at 10^@ C to make the final temperature as 40^@ C will be

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