In a thermodynamic process helium gas ob...

In a thermodynamic process helium gas obeys the law `TP^(-2//5)` = constant,If temperature of `2` moles of the gas is raised from `T` to `3T`, then

heat given to the gas is 9RT

heat given to the gas is zero

increase in internal energy is 6RT

work done by the gas is -6RT

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