Rate of heat flow through a cylindrical rod is `H_(1)`. Temperatures of ends of rod are `T_(1)` and `T_(2)`. If all the dimensions of rod become double and temperature difference remains same and rate of heat flow becomes `H_(2)`. Then `(H_(1))/(H_(2))` is `0.x`. Find value of x.

A cylinderical rod has temperature T_(1) and T_(2) at its ends. The rate of flow of heat is Q^(1) cal/s. if all the linear dimensions are doubled keeping temperature constant then rate of flow of heat Q_(2) will be

A cylindrical rod having temperature T_(1) and T_(2) at its ends. The rate of flow of heat is Q_(1) cal//sec . If all the linear dimensions are doubled keeping temperature constant, then rate of flow of heat Q_(2) will be

The rate of heat flow through a slab is P_("cond") . If the slab thickness is doubled, its cross-sectional area is halved, and the temperature difference across it is doubled, then the rate of heat flow becomes

The heat is flowing through two cylinderical rods of same material. The diameters of the rods are in the ratio 1:2 and their lengths are in the ratio 2:1 . If the temperature difference between their ends is the same, the ratio of rates of flow of heat through them will be

The ratio of the diameters of two metallic rods of the same material is 2 : 1 and their lengths are in the ratio 1 : 4 . If the temperature difference between their ends are equal, the rate of flow of heat in them will be in the ratio

Rate of heat flow through two conducting rods of identiclal dimensions having thermal conductivities K_(1) and K_(2) and Q_(1) and Q_(2) when their ends are maintained at the same difference of temperature individually. When the two rods are joined in series with their ends maintained at the same temperature difference (as shown in the figure), the rate of heat flow will be

Find the rate of heat flow through a cross section of the rod shown in figure (theta_(2)gttheta_(1) . Thermal conductivity of the material of the rod is K.

1 kcal of heat flowing through a rod of iron.When the rod is cut down to 4 pieces then what will be the heat flowing through each piece having same differential temperature ?

Heat is flowing through two cylindrical rods made of same materials whose ends are maintained at similar temperature. If diameters of the rods are in ratio 1:2 and lengths in ratio 2:1 , then the ratio of thermal current through them in steady state is:

Two rods one is semi circular of thermal conductivity K_(1) and otheir is straight of thermal conductivity K_(2) and of same cross sectional area are joined as shown in the The points A and B are maintained at same temperature difference. If rate of flow of heat is same in two rods then K_(1)//K_(2) is .