if `y=3x+6x^2+10x^3+................` then the value of `x` in terms of `y` is
(i) `1-(1-y)^(-1/3)`
(ii) `1-(1+y)^(1/3)`
(iii) `1+(1+y)^(-1/3)`
(iv) `1-(1+y)^(-1/3)`

Find the real values of x and y if (x-1)/(3+1)+(y-1)/(3-i)=i

Find the value of x and y (1)/(2x)+(1)/(3y)=2 (1)/(3x)+(1)/(2y)=(13)/(6)

If y=3^(x-1)+3^(-x-1) , then the least value of y is

If ((1+i)/(1-i))^(3)-((1-i)/(1+i))^(3)=x+i y then (x, y)=

x-y relation is given by y=x^(n) calculate the value of n in the following :- (i) y=(x^(2))/(x^(2//3)) (ii) y=(x^(3//2))/(x^(1)) (iii) y=(x^(1//2))/(x^(1//2)) (iv) y=(x^(3//2))/(sqrt(x))

x-y relation is given by y=x^(n) calculate the value of n in the following :- (i) y=(x^(2))/(x^(2//3)) (ii) y=(x^(3//2))/(x^(1)) (iii) y=(x^(1//2))/(x^(1//2)) (iv) y=(x^(3//2))/(sqrt(x))

x-y relation is given by y=x^(n) calculate the value of n in the following :- (i) y=(x^(2))/(x^(2//3)) (ii) y=(x^(3//2))/(x^(1)) (iii) y=(x^(1//2))/(x^(1//2)) (iv) y=(x^(3//2))/(sqrt(x))

If x=3, y=2 and z=-1 , then the value of (x^3+y^3+1)/(y^3-z^3) is

If xy(x + y) = 1 then,the value of 1/(x^3 y^3) -x^3 - y^3 is

"Find the value of "(x+y)," if "(x+(y^(3))/(x^(2)))^(-1)-((x^(2))/(y)+(y^(2))/(x))^(-1)+((x^(3))/(y^(2))+y)^(-1)=(1)/(3)