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% hydrolysis of 0.1M CH(3)COONH(4), when...

`%` hydrolysis of 0.1M `CH_(3)COONH_(4),` when `K_(a)(CH_(3)COOH)=K_(b)(NH_(4)OH)=1.8xx10^(-5)` is:

A

`0.55`

B

`7.63`

C

`0.55xx10^(-2)`

D

`7.63xx10^(-3)`

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Both conc. Being 1 M, the factor by which the percent hydrolysis of CH_3COO^- is greater in CH_3COONH_4 than in CH_3COONa is : [K_a(CH_3COOH)=K_b(NH_4OH)=1.8xx10^(-5)]

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