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The solubility of AgBrO(3) (formula mass...

The solubility of `AgBrO_(3)` (formula mass=236) is `0.0072` g in 1000 mL. What is the `K_(sp)`?

A

`2.2xx10^(-8)`

B

`3.0xx10^(-10)`

C

`3.0xx10^(-5)`

D

`9.3xx10^(-10)`

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Knowledge Check

  • The solubility of AB_(2) is 0.05 g per 100 mL at 25^@ C .Calculate K_(sp) of AB_(2) at 25^(@)C ? [Atomic mass of A = 20 amu, atomic mass of B = 40 amu]

    A
    `10^(3)`
    B
    `5 xx 10^(-7)`
    C
    `10^(-6)`
    D
    `5 xx 10^(-3)`

  • The solubility in terms of K_(sp) "for " A_3B_((aq)) is

    A
    `(K_(sp)/3)^(1//4)`
    B
    `(K_(sp)/27)^(1//4)`
    C
    `(27K_(sp)) ^(1//4)`
    D
    `(3K_(sp)) ^(1//4)`

  • The solubility of A_(2)B_(3) is "x mol dm"^(-3) . Its K_(sp) is

    A
    `6x^(4)`
    B
    `64x^(4)`
    C
    `36x^(5)`
    D
    `108x^(5)`
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