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The solubility product of AgCl is 10^(-1...

The solubility product of `AgCl` is `10^(-10)M^(2)`. The minimum volume ( in `m^(3))` of water required to dissolve `14.35 mg` of `AgCl` is approximately `:`

A

`0.01`

B

`0.1`

C

100

D

10

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