|[1,q,bc],[1,b,ca],[1,c,ab]|

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Evaluate: |[1,a,bc],[1,b,ca],[1,c,ab]|

Evaluate : triangle = |[1,a,bc],[1,b,ca],[1,c,ab]|

Using properties of determinants prove the following. abs[[1,a,bc],[1,b,ca],[1,c,ab]]=(a-b)(b-c)(c-a)

|[1,a,bc] , [1,b,ca] , [1,c,ab]|=

|[1,1,1],[a,b,c],[bc,ca,ab]|=(a-b)(b-c)(c-a)

|[1,a, bc] ,[1, b, ca], [1, c, ab]| = (a-b)(b-c)(c-a)

Show without expanding at any stage that: [1/a, a,bc],[1/b,b,ca],[1/c, c, ab]|=0

Evaluate Delta -|(1,a,bc),(1,b,ca),(1,c,ab)|

Factorise : |(1,a,bc),(1,b,ca),(1,c,ab)|

Prove that: {:|(1,a,bc),(1,b,ca),(1,c,ab)|=(a-b)(b-c)(c-a)