In a ` Delta ABC,B=pi/8 and C=(5 pi)/8` and the altitude `AD=h.` Then h : a is equal to

In a Delta ABC, B = pi//8 and C = 5pi //8 and the atitude AD=h. Then h:a is equal to

In a triangleABC,B=pi/8, C=(5pi)/(8) . The altitude from A to the side BC, is

In a triangleABC,B=pi/8, C=(5pi)/(8) . The altitude from A to the side BC, is

In a triangleABC,B=pi/8, C=(5pi)/(8) . The altitude from A to the side BC, is

In Delta ABC,a=2b and |A-B|=(pi)/(3) then /_C is

In triangle ABC, dedians AD and CE are drawn.If /_DAC=(pi)/(8), and /_ACE=(pi)/(4) then the area of the triangle ABC is equal to (25)/(9) (b) (25)/(3)(c)(25)/(18) (d) (10)/(3)

In a triangle ABC, medians AD and CE are drawn.If AD=5,/_DAC=(pi)/(8) and /_ACE=(pi)/(4) then the area of the triangle ABC is equal to (5a)/(b), then a+b is equal to

In a triangle ABC, medians AD and CE are drawn. If AD=5, angle DAC=pi/8 and angle ACE=pi/4 then the area of the triangle ABC is equal to (5a)/b, then a+b is equal to

In an acute angle triangle ABC, AD, BE and CF are the altitudes, then (EF)/a+(FD)/b+(DE)/c is equal to -