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If the equation x^(2)+4+3sin(ax+b)-2x=0 ...

If the equation `x^(2)+4+3sin(ax+b)-2x=0` has at least one real solution, where `a,b in [0,2pi]` then one possible value of `(a+b)` can be equal to

A

`(7pi)/2`

B

`(5pi)/2`

C

`(9pi)/2`

D

None of these

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The correct Answer is:
A
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