Inverse of the matrix `[[cos2theta,-sin2theta],[sin2theta,cos2theta]]` is

Inverse of the matrix A=[[cos2theta, -sin2theta], [sin2theta, cos2theta]] is

Inverse of the matrix [[cos2 theta,-sin2 thetasin2 theta,cos2 theta]] is

Inverse of the matrix [[cos 2 theta,-sin 2 theta],[sin 2 theta , cos 2 theta]] is

Inverse of the matrix [(cos 2 theta,-sin 2theta),(sin 2 theta, cos 2theta)] is

Inverse of the matrix [{:(cos 2 theta, -sin 2 theta),(sin 2 theta, cos 2 theta):}] is

Find the inverse of the matrix [(cos theta, sin theta),(-sin theta, cos theta):}]

Write the inverse of the matrix {:|(cos theta,sin theta),(-sin theta,cos theta)| .

If A=[[cos 2 theta, sin 2 theta],[-sin2theta, cos2theta]] , find A^2

If A=[[cos 2 theta, sin 2 theta],[-sin2theta, cos2theta]] , find A^2

If A=[[costheta,sintheta],[-sintheta,costheta]] then prove that A^2=[[cos2theta,sin2theta],[-sin2theta,cos2theta]]