If `sum_(r=0)^(n-1)(("^nC_r)/(^nC_r+^nC_(r+1)))^3=4/5` then n=

If sum_(r=0)^(n-1)((^nC_(r))/(nC_(r)+^(n)C_(r+1)))^(3)=(4)/(5) then n=

The value of sum_(r=0)^(n-1) (""^nC_r)/(""^nC_r+ ""^n C_(r+1)) equals a. n+1 b. n/2 c. n+2 d. none of these

sum_(r=1)^(10) r. (""^nC_r)/(""^nC_(r-1)) =

The value of sum_(r=0)^(n-1)(nC_(r))/(nC_(r)+^(n)C_(r+1)) is eqaul to

Find sum_(r=0)^n(r+1)*"^nC_rx^r

Find the sum sum_(r=1)^(n)r^(2)(^nC_(r))/(n_(C_(r-1)))

Find the sum of sum_(r=1)^(n)(r^(n)C_(r))/(^nC_(r-1))

sum_(r=1)^(n) (-1)^(r-1) ""^nC_r(a - r) =

sum_(r=1)^(n) (-1)^(r-1) ""^nC_r(a - r) =

Find the sum sum_(r=1)^n r^n (^nC_r)/(^nC_(r-1)) .