A charge particle `q_(1)`, is at position (2, -1, 3). The electrostatic force on another charged particle `q_(2)` at (0, 0, 0) is :

Three particles are fixed on an x axis. Particle 1 of charge q_(1) is at x = -a, and particle 2 charge q_(2) is at x = +a. If their net electrostatic force on particle 3 of charge +Q is to be zero, what must be the ratio q_(1)//q_(2) when particle 3 is at (a) x = +0.750 a and (b) x = +1.50 a ?

In Fig. four particles form a square. The charges are q_(1) = q_(4) = Q and q_(2) = q_(3) = q . (a) What is Q/q is the net electrostatic force on particles 2 and 3 is zero ? (b) Is there any value of q makes the net electrostatic force on each of the four particles zero ? Explain.

A charged particle of mass m_(1) and charge q_(1) is revolving in a cricle of radius r. another charged particle of charge q_(2) and mass m_(2) is situated at the centre of the circle. If the velocity and time period of the revolving particle be v and T respectively, then,

A charged particle of mass m_(1) and charge q_(1) is revolving in a circle of radius r .Another charged particle of charge q_(2) and mass m_(2) is situated at the centre of the circle.If the velocity and time period of the revolving particle be v and T respectively then

In Fig., three charged particles lie on an x axis. Particles 1 and 2 are fixed in place. Particle 3 is free to move, but the net electrostatic force on it from particles 1 and 2 happens to be zero. If 2.0 L_(23) = L_(12) , what is the ratio q_(1)//q_(2) ?

In Fig., particle 1 of charge +6.0 mu C and particle 2 of charge -2.0 mu C are held at separation L = 10.0 cm on an x axis. If particle 3 of unknown charge q_(3) is to be located such that the net electrostatic force on it from particles 1 and 2 is zero, what must be the (a) x and (b) y coordinates of particle 3 ?