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[" (2) Solve the following eq "],[" (a) ...

[" (2) Solve the following eq "],[" (a) "10p=100]

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Given the ionic equivalent conductivities for the following ions : lambda^(@)._(eq)K^(o+)=73.5cm^(2)ohm^(-1)eq^(-1) lambda^(@)._(eq)Al^(3+)=149cm^(2)ohm^(-1)eq^(-1) lambda^(@)._(eq)SO_(4)^(2-)=85.8cm^(2)ohm^(-1)eq^(-1) The wedge_(eq)^(@) for potash alum (K_(2)SO_(4).Al_(2)(SO_(4))_(3).24H_(2)O) is :

Given the ionic equivalent conductivities for the following ions : lambda^(@)._(eq)K^(o+)=73.5cm^(2)ohm^(-1)eq^(-1) lambda^(@)._(eq)Al^(3+)=149cm^(2)ohm^(-1)eq^(-1) lambda^(@)._(eq)SO_(4)^(2-)=85.8cm^(2)ohm^(-1)eq^(-1) The wedge_(eq)^(@) for potash alum (K_(2)SO_(4).Al_(2)(SO_(4))_(3).24H_(2)O) is :

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Calculating the thermodynamic equilibrium constant from the cell emf : The standard emf for the following galvanic cell is 0.46 V Cu(s)|Cu^(2+)(aq.)||Ag^(+)(aq.)|Ag(s) Calculate the equilibrium cosntant K_(C) for the reaction Cu(s)+2Ag^(+)(aq.)hArr Cu^(2+)(aq.)+2Ag(s) Strategy : Substitute the standard emf into the Equation (3.9) realting this quantity to the thermodynatmic equilibrium constant, K_(eq.). Solve K_(eq.). Note that K_(eq.). = K_(C^(.))